memccpy, memchr, memcmp, memcpy, memmove, memset – memory operations|
void* memccpy(void *s1, void *s2, int c, ulong n)
void* memchr(void *s, int c, ulong n)
int memcmp(void *s1, void *s2, ulong n)
void* memcpy(void *s1, void *s2, ulong n)
void* memmove(void *s1, void *s2, ulong n)
void* memset(void *s, int c, ulong n)
These functions operate efficiently on memory areas (arrays of
bytes bounded by a count, not terminated by a zero byte). They
do not check for the overflow of any receiving memory area. |
Memccpy copies bytes from memory area s2 into s1, stopping after the first occurrence of byte c has been copied, or after n bytes have been copied, whichever comes first. It returns a pointer to the byte after the copy of c in s1, or zero if c was not found in the first n bytes of s2.
Memchr returns a pointer to the first occurrence of byte c in the first n bytes of memory area s, or zero if c does not occur.
Memcmp compares its arguments, looking at the first n bytes only, and returns an integer less than, equal to, or greater than 0, according as s1 is lexicographically less than, equal to, or greater than s2. The comparison is bytewise unsigned.
Memcpy copies n bytes from memory area s2 to s1. It returns s1.
Memmove works like memcpy, except that it is guaranteed to work if s1 and s2 overlap.
Memset sets the first n bytes in memory area s to the value of
byte c. It returns s.
All these routines have portable C implementations in /sys/src/libc/port.
Most also have machine–dependent assembly language implementations
ANSI C does not require memcpy to handle overlapping source and
destination; on Plan 9, it does, so memmove and memcpy behave
If memcpy and memmove are handed a negative count, they abort.